n^2+5n-500=0

Solution for n^2+5n-500=0 equation:

n^2+5n-500=0

a = 1; b = 5; c = -500;
Δ = b2-4ac
Δ = 52-4·1·(-500)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-45}{2*1}=\frac{-50}{2}
=-25
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+45}{2*1}=\frac{40}{2}
=20
$